Find the product of :
(5a+b-3c)^2
Answers
Answered by
3
= (5a+b-3c)(5a+b-3c)
= 25a^2+5ab -15ac +5ab+b^2-3bc -15ac-3cb+9c^2
= 25a^2 +10ab -30ac-9bc+9c^2
answer= 25a^2+9c^2+10ab-30ac-9bc
= 25a^2+5ab -15ac +5ab+b^2-3bc -15ac-3cb+9c^2
= 25a^2 +10ab -30ac-9bc+9c^2
answer= 25a^2+9c^2+10ab-30ac-9bc
singhkamla:
actually the answer is totally wrong
the ans is 25a^2+b^2+9c^2+10ab-6bc-30ac
it is correct
my answer is correct
how you got , evidence???
my book
what book
in my book there is the ans
sorry
it's ok
Answered by
0
Answer:
25a² + b² - 9c²
Step-by-step explanation:
(5a + b-3c)²
= 25a² + b² - 9c²
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