Math, asked by IayushI, 1 year ago

find the product of -5x²y, -2/3xy²z, 8/15xyz² and -1/4z. verify the result when x=1, y=2 and z=3.​

Answers

Answered by harendrachoubay
8

The product of ( - 5x^{2}y) × ( - \frac{2}{3}·x·y^{2}·z) ×

( \frac{8}{15}·xy·z^{2}) × (\frac{- 1}{4}·z) is - "\frac{4}{9}·x^{4}·y^{4}·z^{2}".

Step-by-step explanation:

We have,

( - 5x^{2}y) × ( - \frac{2}{3}·x·y^{2}·z) ×

( \frac{8}{15}·xy·z^{2}) × (\frac{- 1}{4}·z)

= ( - 5 × \frac{2}{3} × \frac{8}{15} × \frac{1}{4}) ×

x^{4} × y^{4} × z^{2}

= - \frac{4}{9}·x^{4}·y^{4}·z^{2}

∴ The product of ( - 5x^{2}y) × ( - \frac{2}{3}·x·y^{2}·z) ×

( \frac{8}{15}·xy·z^{2}) × (\frac{- 1}{4}·z) is - \frac{4}{9}·x^{4}·y^{4}·z^{2}.

Put x = 1, y = 2 and z = 3

- \frac{4}{9}·1^{4}·2^{4}·3^{2}

=  - \frac{4}{9}·1·16·9

= - 64

Answered by ThePureSoul
1

Step-by-step explanation:

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