find value of 30 degree for all trigonometric ratios geometrically
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Let a rotating line OX−→− rotates about O in the anti-clockwise sense and starting from the initial position OX−→− traces out ∠XOY = 30°.
Trigonometrical Ratios of 30°
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Take a point P on OY−→− and draw PA perpendicular to OX−→− Then, ∠OPA = 60°.
Now, produce PA to B such that PA = MB and join OB.
From ∆PMO and ∆QMO we have,
PA = BA,
OA common
and ∠OBP = ∠OPB = 60°
Therefore, ∠POB = 30° + 30° = 60°; which shows that each angel of triangle OPQ is 60° . Hence ∆OPQ is equilateral.
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