Question

Find the product of (-7x^2y^3z),(-13y^2) and yz

Answer 1

Given,

$\[\left( { - 7{x^2}{y^{3z}}} \right),\left( { - 13{y^2}} \right),\left( {yz} \right)\]$

Solution,

Calculate the product.

$\[\begin{array}{l} = \left( { - 7{x^2}{y^{3z}}} \right) \times \left( { - 13{y^2}} \right) \times \left( {yz} \right)\\ = - 7{x^2}{y^{3z}} \times \left( { - 13} \right){y^2} \times yz\\ = 91{x^2}{y^{3z}} \times {y^2} \times yz\\ = 91{x^2}{y^{3z + 3}}z\end{array}\]$

Hence the product is $\[91{x^2}{y^{3z + 3}}z\]$