Question

find the product of 8 + 3 into root under 2 and 8 - 3 into root under 2

Answer 1

(8 + 3√2)*(8-3√2)

We know that (a+b)*(a-b) = a²-b²

So (8 + 3√2)*(8-3√2) = 8² - 3²*2 = 64-18 = 46