Question

Find the product of (a+b+c) and (a+b-c) and then evaluate the product for a=1 b=-1 c=2

Answer 1

Answer:

(a+b+c)=2

(a+b-c)=-2

Step-by-step explanation:

Answer 2

Given:

We have an equation (a+b+c) and (a+b-c) .

To Find:

We need to find the product when a=1,b = -1 ,c=2

Step-by-step explanation:

• We have the given terms which are (a+b+c) and (a+b-c) .

• First of all we find the products of these terms be simply multyplying them we get

                     $(a+b+c)(a+b-c)$

• Now simply multiply each term of one brackets with other terms bracket we get the result

            $(a+b+c) (a+b-c) =a^2+ab-ac+ba+b^2-bc+ac+cb-c^2$

• Now take the like terms together we get

         $=a^2+b^2-c^2+ab+ba-ac+ac-bc+cb\\=a^2+b^2-c^2+2ab$

• Now we will put the value in the above equation a = 1,b = -1, c =2 we get

                 $=(1)^2+(-1)-(2)^2+2(1)(-1)\\=1+1-4-2\\=-4$

Hence, the product of given terms is 4.