Math, asked by nishachakraborty77, 9 months ago

find the product of given question

(a²+2ab+2bc+2ca) (a+b-c-1)

Answers

Answered by arpv2020
2

Answer:

a^3-a^2+2[ab(a+b)+bc(b-c)+ca(a-c)-ab-bc-ca+abc]

Step-by-step explanation:

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(a+b-c-1)(a^2+2ab+2bc+2ca)

a(a^2+2ab+2bc+2ca)+b(a^2+2ab+2bc+2ca)-c(a^2+2ab+2bc+2ca)-1(a^2+2ab+2bc+2ca)

(a^3+2a^2b+2abc+2ca^2)+(a^2+2ab^2+2b^2c+2abc)-(a^2+2abc+2bc^2+2c^2a)

-(a^2+2ab+2bc+2ca)

a^3+2a^2b+2abc+2ca^2+a^2+2ab^2+2b^2c+2abc-a^2-2abc-2bc^2-2c^2a-a^2-2ab-2bc-2ca

After this step you will take out common term of each single term and then common of whole expression. You will get final answer written above in bold.

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Answered by Anonymous
3

Step-by-step explanation:

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