Question

find the product of h(x) = 6x²-7x+1 and f(x) =5x-7​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Given Polynomial:

Given Polynomial:g(x) = 6x^2 - 7x + 1

Given Polynomial:g(x) = 6x^2 - 7x + 1f(x) = 5x - 7

Given Polynomial:g(x) = 6x^2 - 7x + 1f(x) = 5x - 7Solution:

Given Polynomial:g(x) = 6x^2 - 7x + 1f(x) = 5x - 7Solution:f(x) = 5x = 7

Given Polynomial:g(x) = 6x^2 - 7x + 1f(x) = 5x - 7Solution:f(x) = 5x = 7f(x) = x = 7/5

Given Polynomial:g(x) = 6x^2 - 7x + 1f(x) = 5x - 7Solution:f(x) = 5x = 7f(x) = x = 7/5By putting the value of x in g(x), we get

Given Polynomial:g(x) = 6x^2 - 7x + 1f(x) = 5x - 7Solution:f(x) = 5x = 7f(x) = x = 7/5By putting the value of x in g(x), we getg(x) = 6(7/5)^2 - 7(7/5) + 1

Given Polynomial:g(x) = 6x^2 - 7x + 1f(x) = 5x - 7Solution:f(x) = 5x = 7f(x) = x = 7/5By putting the value of x in g(x), we getg(x) = 6(7/5)^2 - 7(7/5) + 1g(x) = 6(49/25) - 49/5 + 1

Given Polynomial:g(x) = 6x^2 - 7x + 1f(x) = 5x - 7Solution:f(x) = 5x = 7f(x) = x = 7/5By putting the value of x in g(x), we getg(x) = 6(7/5)^2 - 7(7/5) + 1g(x) = 6(49/25) - 49/5 + 1g(x) = 294/25 - 49/5 + 1

Given Polynomial:g(x) = 6x^2 - 7x + 1f(x) = 5x - 7Solution:f(x) = 5x = 7f(x) = x = 7/5By putting the value of x in g(x), we getg(x) = 6(7/5)^2 - 7(7/5) + 1g(x) = 6(49/25) - 49/5 + 1g(x) = 294/25 - 49/5 + 1g(x) = 74/25

Given Polynomial:g(x) = 6x^2 - 7x + 1f(x) = 5x - 7Solution:f(x) = 5x = 7f(x) = x = 7/5By putting the value of x in g(x), we getg(x) = 6(7/5)^2 - 7(7/5) + 1g(x) = 6(49/25) - 49/5 + 1g(x) = 294/25 - 49/5 + 1g(x) = 74/25Answer:

Given Polynomial:g(x) = 6x^2 - 7x + 1f(x) = 5x - 7Solution:f(x) = 5x = 7f(x) = x = 7/5By putting the value of x in g(x), we getg(x) = 6(7/5)^2 - 7(7/5) + 1g(x) = 6(49/25) - 49/5 + 1g(x) = 294/25 - 49/5 + 1g(x) = 74/25Answer:74/25