find the product of the following
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(a−b)(a+b)+(b−c)(b+c)+
(c−a)(c+a)=0
LHS=a 2−b 2 −ab+ab+b 2−c 2 +
bc−bc+c 2−a 2−ac+ac
we see the terms cancel each other hence equation reduced to zero
Or we can also use identity (a−b)(a+b)=a 2 −b 2 to find similar result.
Hope it helps!
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