Math, asked by naira01175, 11 months ago

find the product of the following binomial​

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Answered by Anonymous
8

2/5a(a^2-1/5b^2)+b(a ^2-1/5b^2)

2/5a^3-2/25ab^2+ba^2-1/5b^3


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Answered by sahistajawed
8

ii) (7p - 3q) (2p + 5q)

7p*2p +7p*5q - 3q*2p - 3q*5q

14p^2 + 35pq - 6pq - 15q^2

14p^2 + 29pq - 15q^2 (answer)

(iii) (2/5a + b) (a^2 - 1/5b^2)

2/5*a^2 - 2/5*1/5b^2 +b*a^2 -b*1/5b^2

2/5a^3 - 2/25ab^2 + a^2b - 1/5b^3 (Answer)

v) (4x^2 + 7y^3)(3xy - 2y^2)

12x^3y - 8x^2y^2 + 21xy^4 - 14 y^5(answer)

vi) (1.1x + 2.7y) (1.1x - 2.7 y)

This equation is in a^2 - b^2

Therefore, the answer is

(1.1x) ^2 - (2.7y)^2


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