Question

find the product of this

Answer 1

$\frac{x^{4}y^{5}}{5}$

$\frac{3}{5} xy*\frac{5}{6} x^{2} y*\frac{2}{5} xy^{3}\\=\frac{1}{5} xy*\frac{5}{2} x^{2} y*\frac{2}{5} xy^{3}\\\\=\frac{1}{1} xy*\frac{1}{2} x^{2} y*\frac{2}{5} xy^{3}\\\\=\frac{1}{1} xy*\frac{1}{1} x^{2} y*\frac{1}{5} xy^{3}\\\\=xy*x^{2}y*\frac{xy^{3}}{5} \\=\frac{x^{4}y^{5}}{5}$

step:

Answer 2

all get cancelled like this
$\frac{3}{5} xy \times \frac{5}{6} {x}^{2} y \times \frac{2}{5} x {y}^{3}$
1. in 3 by 5 ..5 and 5 get cancelled
2. in 5 by 6 and 2 by 5 .. 2 threes 6 and 3 and the numerator 3 get cancelled and the remaining part 5 is left as 1 by 5 i.e.,
1 divided by 5
$\frac{1}{5}$
and we have
$xy \times {x}^{2} y \times x {y}^{3}$
it is solved as
${x}^{4 } {y}^{5} and .$
the answer is....
$\frac{1}{5} {x}^{4} {y}^{5}$