Find the product of two consecutive natural numbers is 210 then determine the numbers
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let the 1st natural no. be=x
other natural no.=x+1
ATQ,
x(x+1)=210
implies that, x^2+x =210
or, x^2 +x-210=0
or, x^2+15x-14x-210=0
or, x(x+15)-14(x+15)=0
or, (x+15)(x-14)=0
implies that, x=15 rejecting -14 as it is not a natural no.
Therefore 1st no=15
other no.=15+1=16 ANS
other natural no.=x+1
ATQ,
x(x+1)=210
implies that, x^2+x =210
or, x^2 +x-210=0
or, x^2+15x-14x-210=0
or, x(x+15)-14(x+15)=0
or, (x+15)(x-14)=0
implies that, x=15 rejecting -14 as it is not a natural no.
Therefore 1st no=15
other no.=15+1=16 ANS
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