Question

Find the product of (x-3) (x+3) (x^2+9)

Answer 1

Answer:

Apply the formula:-(a+b)(a-b)=a^2-b^2

(x+3)(x-3)(x^2+9)

=(x^2-9)(x^2+9)

Again apply the formula:-(a+b)(a-b)=a^2-b^2

=x^4-81

This will be the answer.

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Answer 2

$(x - 3)( x + 3)( {x}^{2} + 9) = 0$

$({x}^{2} - 9)( {x}^{2} + 9) = 0$

${x}^{4} - 81 = 0$

${x}^{4} = 81$

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