Question

find the product of (x+3y)(x2-3xy+9y2)

Answer 1

here is your answer

Answer 2

Concept:

Mathematical expression is a mathematical relation or statement or term involves various mathematical quantities, numbers, mathematical operations, variable and other mathematical components etc.

From mathematical identity of cube formula for factorization we have,

$(a+b)(a^2-ab+b^2)=a^3+b^3$

Given:

Given that, the expression is given by $(x+3y)(x^2-3xy+9y^2)$.

Find:

The product of the above algebraic expression.

Solution:

Given that, the algebraic expression is given by,

$(x+3y)(x^2-3xy+9y^2)$

$=(x+3y)\{(x)^2-x.3y+(3y)^2\}$, rearranging the given expression in order

Comparing to the given algebraic identity of cube value for factorization we get,

a = x and b = 3y

So the value of the product becomes $=a^3+b^3=x^3+(3y)^3=x^3+27y^3$

Hence the product of $\mathbf{(x+3y)(x^2-3xy+9y^2)=x^3+27y^3}$.

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