Question

find the product of (x2 +y) (3x-y-2)​

Answer 1

Step-by-step explanation:

(

3

−

−

2

)

⋅

2

+

(

3

−

−

2

)

{\color{#c92786}{(3x-y-2) \cdot x^{2}}}+y(3x-y-2)

(3x−y−2)⋅x2+y(3x−y−2)

3

3

−

⋅

2

−

2

2

+

(

3

−

−

2

)

Answer 2

Answer:

$3x^{3} -x^{2} y-2x^{2} +3xy-y^{2} -2y$

Step-by-step explanation:

Given : $(x^{2} +y)(3x-y-2)$

To find : Product of the given terms

Solution :

• The given expression is

      $(x^{2} +y)(3x-y-2)$

• Multiplying both the brackets, we get

       $(x^{2} +y)(3x-y-2) = x^{2} (3x-y-2)+y(3x-y-2)$

                                  $= 3x^{3} -x^{2} y-2x^{2} +3xy-y^{2} -2y$