Question

| Find the product of zeroes of the quadratic polynomial p(x) = (K-2)x2 - 4x + k is 3 write
the value of K.​

Answer 1

Correct question: If the product of the quadratic polynomial p(x) = (k - 2)x² - 4x + k is 3. Find the value of k

SOLUTION :

Given,

Quadratic polynomial = (k - 2)x² - 4x + k is 3.

Product of zeroes = 3

Value of k =?

We know that,

Using coefficients, the product of zeroes = c/a

c/a = 3

From the above quadratic polynomial,

a = k - 2 c = k

=> k/(k - 2) = 3

=> k = 3(k - 2)

=> k = 3k - 6

=> 6 = 3k - k

=> 2k = 6

=> k = 6/2

Therefore, the value of k is 3.

Answer 2

Correct question : If the product of the zeroes of quadratic polynomial p(x) = (k-2)x² -4x +k is 3 . Find the value of k .

Solution :

P(x) = (k-2)x² -4x +k

Given that product of zeroes =3

We know that product of zeroes of polynomial =c/a

Here ,

a= (k-2)

b= -4

and c = k

So

c/a =3

$\rightarrow \frac{k}{k - 2} = 3$

→k=3(k-2)

→k= 3k -6

→6 =3k-k

→6 =2k

→6/2 =k

→3 = k

Hence the value of k is 3 .