find the product using the identity (a+b)(a-b)=a²-b² (x+p)(x-p)
Answers
Answered by
0
Answer:
x²-p² is the answer
Step-by-step explanation:
(x+p) (x-p)
since (a+b)(a-b)=a²-b²
so,(x)²-(p)²
Therefore x²-p²
Hope it is helpful
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Answered by
0
Step-by-step explanation:
Answer:
(27 {x}^{3} - 3 \times 9 {x}^{2} \times 4y + 3 \times 3x \times 16 {y}^{2} - 64 {y}^{3} ) - (27 {x}^{3} + 3 \times 9 {x}^{2} \times 4y + 3 \times 3x \times 16 {y}^{2} + 64 {y}^{3} ) = 2( - 108 {x}^{2} y - 64 {y}^{3} ) = - 216 {x}^{2} y - 128 {y}^{3}(27x
3
−3×9x
2
×4y+3×3x×16y
2
−64y
3
)−(27x
3
+3×9x
2
×4y+3×3x×16y
2
+64y
3
)=2(−108x
2
y−64y
3
)=−216x
2
y−128y
3
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