find the product: (x/2+3x/5-2)(x/3-3x/5+2
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(x/2+3x/3)(x/3-3x/7)
=x/2(x/3-3x/7)+3x/3(x/3-3x/7)
=x^2/6-3x^2/14+3x^2/9-9x^2/21
=126x^2-27x^2+42x^2-54x^2/126
=x^2(126-27+42-54)/126
=x^2(87)/126
=87x^2/126
so answer is 87x^2/126
=x/2(x/3-3x/7)+3x/3(x/3-3x/7)
=x^2/6-3x^2/14+3x^2/9-9x^2/21
=126x^2-27x^2+42x^2-54x^2/126
=x^2(126-27+42-54)/126
=x^2(87)/126
=87x^2/126
so answer is 87x^2/126
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