Question

find the product:- (x^2-5x +8) × (x^2+2)​

Answer 1

$\sf \: ({x}^{2} - 5x + 8) \times ( {x}^{2} + 2) \\ \sf \implies \: {x}^{2} ( {x}^{2} + 2) - 5x( {x}^{2} + 2) + 8( {x}^{2} + 2) \\ \sf \implies \: {x}^{4 } + 2 {x}^{2} - {5x}^{3 } - 10x + 8 {x}^{2} + 16 \\ \sf \implies \: {x}^{4} - {5x}^{3} + {2x}^{2} + {8x}^{2} - 10x + 16 \\ \red{\sf \implies \: {x}^{4} - {5x}^{3} + {10x}^{2} - 10x + 16 }$

Answer 2

Answer:

$(x2−5x+8)×(x2+2)⟹x2(x2+2)−5x(x2+2)+8(x2+2)⟹x4+2x2−5x3−10x+8x2+16⟹x4−5x3+2x2+8x2−10x+16⟹x4−5x3+10x2−10x+16$

hope it helps ✌