Question

find the product (x-2y+3)(x²+4y²+2xy-3x+6y+9)​

Answer 1

Answer:

Answer

Given : (x−2y+3)(x

2

+4y

2

+2xy+6y−3x+9)

The given question can be written as

=(x+(−2y)+30(x

2

+(−2y)

2

+3

2

−(x)(−2y)−(−2y)(3)−(3)(x))

According to the equation,

a

3

+b

3

+c

3

−3abc=(a+b+c)(a

2

+b

2

+c

2

−ab−bc−ca)

we get,

=x

3

+(−2y)

3

+3

3

−3×x×(−2y)×3

(x−2y+3)(x

2

+4y

2

+2xy+6y−3x+9)=x

3

−8y

3

+27+18xy

Step-by-step explanation:

hope it will work

Answer 2

$\underline\purple{\underline{\sf{\maltese\: Given\::-}}}$

(x - 2y + 3)(x² + 4y² + 2xy + 6y - 3x + 9)

$\underline\purple{\underline{\sf{\maltese\: Identity\: used\::-}}}$

$\red\tt\boxed{a³ + b³ + c³ - 3abc = (a + b + c)(a² + b² + c²ab-bc-ca)}</p><p></p><p></p><p>[tex]\underline\purple{\underline{\sf{\maltese\: Explanation\::-}}}$

$\red\rightdasharrow$ $\rm{(x + (-2y) + 30(x² + (−2y)² + 3² - (x)(-2y) (-2y)(3) — (3)(x))}$

$\red\rightdasharrow$$\rm{x³ + (−2y)³ + 3³ − 3 × × × (−2y) × 3}$

$\red\rightdasharrow$$\rm{(x - 2y + 3)(x² + 4y² + 2xy + 6y — 3x +9)= x³ – 8y³ + 27 + 18xy}$