Question

find the product x and y in the following reaction c6h5cl +cuCN gives in the presence of pyridine X + Y​

Answer 1

Answer:

The reaction of C

6

H

5

−N

2

Cl in presence of CuCN is known as Sandmeyer's reaction which led to the formation of benzonitrile which on hydrolysis in presence of water gives benzamide.

C

6

H

5

−N

2

Cl

CuCN

(A)

C

6

H

5

−CN

H

2

O/H

+

(B)

C

6

H

5

−

C

∣∣

O

−NH

2

Hence A is benzonitrile (C

6

H

5

−C≡N) and B is benzamide

⎝

⎛

C

6

H

5

−

C

∣∣

O

−NH

2

⎠

⎞

.

Answer 2

The products X and Y are $C_6H_5Cl$ and $CuCl$.

• The chemical name of $C_6H_5Cl$ is benzene chloride.
• The chemical name of CuCN is copper(I) cyanide.
• When benzene chloride reacts with copper cyanide in presence of pyridine it gives benzene cyanide as a product along with copper chloride.
• The reaction is-
• $C_6H_5Cl+CuCN\rightarrow C_6H_5CN+CuCl$.
• So, 1 molecule of benzene chloride reacts with 1 molecule of copper cyanide in presence of pyridine to give 1 molecule of benzene cyanide as a major product along with 1 molecule of copper chloride.