Question

Find the products using suitable identity:
1) (t –2)(t –2)
2) (3y –2z) (3y + 2z)
3) 105 × 98

Answer 1

Answer:

(t-2) whole of square.

(3y-2z)

Answer 2

1) (t –2)(t –2)                       Identity

= (t-2)²                                  (a-b)²= a²-2ab+b²

=t²-2t×2+2²

=t²-4t+4

2) (3y –2z) (3y + 2z)            (a+b)(a-b)=a²-b²

=(3y)²-(2z)²

=9y²-4z²

3) 105 × 98                           (x+a)(x+b)=x²+(a+b)x+ab

=(100+5)×(100-2)

=(100)²+(5+(-2))100+(-10)

=10000+300-10

=10000+290

=10290

I hope it helps.