Question

Find the Pythagorean triplet whose greatest number is 37.

Answer 1

As we know that 2m,m²+1 and 2m²-1, form a Pythagoras triplet fir any number m>1.

Let, m²+1=37.

= m²=37-1=36

=m=√36

m=> 6.

On putting value of m

2m = 2×6=12

m²-1 = (6)²-1= 35.

Verify:

(37)²=(35)²+ (12)²

1369=1225+144

1369=1369.

Hence, verified!!

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