Find the pythagorean triplet whose one no. is 8
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Answer:
8
2
=64
⇒ 100−64=36
⇒
36
=6
⇒
100
=10
Let
Hypotenuse =10 [ Since its greater than 6 and 8 ]
Base =8 and
Perpendicular =6
(Hypotenuse)
2
=(Perpendicular)
2
+(Base)
2
[ Pythagoras theorem ]
⇒ (10)
2
=(6)
2
+(8)
2
⇒ 100=36+64
⇒ 100=100
∴ Pythagorean triplet are 6,8,10
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