find the pythagorean triplet whose smallest member is 12
Answers
Answered by
108
for finding it we will divide 12 by 2=
12/2=6
now by applying formula n2+1=(6)2+1=36+1=37
other formula=n2 -1=(6)2-1=36-1=35
the ans is 12 35 37
12/2=6
now by applying formula n2+1=(6)2+1=36+1=37
other formula=n2 -1=(6)2-1=36-1=35
the ans is 12 35 37
Anonymous:
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Answered by
2
Step-by-step explanation:
Correct option is
A
5, 12, 13
If we take m
2
-1=12
Then m
2
=12+1=13
Then the value of m will not be an integer
So we try to take m
2
+1=12 Again m
2
=11 will not give an integer value for m
So let us take 2m = 12
then m=6
Thus m
2
−1=36−1=35 and m
2
+1=36+1=37
Therefore the required triplet is 12, 35, 37
Note : All Phythagorean triplets may not be obtained using this form For example another triplet 5, 12, 13 also has 12 as a member
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