Find the Pythagorean triplet whose smallest number is 20.
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Pythagorean triplet whose smallest number is 20 is 20, 99 and 101.
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Answer:
If we take m²-1=20,then m²=20+1=21
Here, the value of m will not be a integer.
Now, let us make m²+1= 20.Again m²=19 will not give an integer value of m.
Let us take 2m=20,which give an integer value of m,which is m=10
Thus, (m²-1)=(10²-1)=(100-1)=99
And,(m²+1)=(10²+1)=(100+1)=101
So,the required triplet is 20,99,101
Hope it helps you
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