Math, asked by krish775751, 7 months ago

Find the Pythagorean triplet whose smallest number is 4

Answers

Answered by Anonymous
49

\orange{\underline{\underline{\huge{\mathfrak{Answer}}}}}

❥ For every natural number m > 2, ( 2m , m² - 1 , m² + 1 ) is a pythagorean triplet and the smallest number is 2m..

✯ Given :

(2m) = 4

=> m = 4/2

=> m = 2

✯ (m² - 1)

= (2² - 1)

= (4 - 1)

= 3

✯ (m² + 1)

= (2² + 1)

= (4 + 1)

= 5

Therefore, the triplet is ( 4 , 3 , 5 )

{\huge{\underline{\small{\mathbb{\pink{Hope \ this \ helped♡}}}}}}

Similar questions