Find the Pythagorean triplet whose smallest number is 4
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❥ For every natural number m > 2, ( 2m , m² - 1 , m² + 1 ) is a pythagorean triplet and the smallest number is 2m..
✯ Given :
(2m) = 4
=> m = 4/2
=> m = 2
✯ (m² - 1)
= (2² - 1)
= (4 - 1)
= 3
✯ (m² + 1)
= (2² + 1)
= (4 + 1)
= 5
Therefore, the triplet is ( 4 , 3 , 5 )
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