Find the Pythagorean triplet whose smallest number is18
Answers
Answered by
2
Answer:
the Pythagorean triplet is 18, 80, and 82.
Answered by
4
Answer :
i) 2m
= 2m = 18
= m = 18/2
= m = 9
ii) m^2 -1
= 9 ^ 2 -1
= 81 - 1
= 80
iii) m^2 + 1
= 9^2 + 1
= 81 + 1
= 82
Therefore, the Pythagorean triplet of 18 are = 18 , 80 and 82.
Similar questions