Question

Find the Pythagorean triplet whose smallest number is18

Answer 1

Answer:

the Pythagorean triplet is 18, 80, and 82.

Answer 2

Answer :

i) 2m

= 2m = 18

= m = 18/2

= m = 9

ii) m^2 -1

= 9 ^ 2 -1

= 81 - 1

= 80

iii) m^2 + 1

= 9^2 + 1

= 81 + 1

= 82

Therefore, the Pythagorean triplet of 18 are = 18 , 80 and 82.