find the Pythagorean triplet with 8 as its smallest number
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We know that
2m, m ^2-1, m ^2+ 1 are pythagorean triplets
2m=8
m=4
m^2-1=4^2-1=15
m^2+1=4^2+1=17
So,8,15,17 are pythagorean triplets
2m, m ^2-1, m ^2+ 1 are pythagorean triplets
2m=8
m=4
m^2-1=4^2-1=15
m^2+1=4^2+1=17
So,8,15,17 are pythagorean triplets
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6&4 are Pythagorean triplet
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