Question

find the Pythagorean triplets one of whose number is 6.
please explain it​

Answer 1

Given ,

A pythagorean triplet in which one member is 12

We know that ,

the general form of pythagorean triplet is given by

For m > 1

$\boxed{ \tt{2m \: , \: m² - 1 \: , \: \: and \: \: m² + 1}}$

Thus ,

➡2m = 6

➡m = 6/2

➡m = 3

Now ,

➡m² - 1

➡(3)² - 1

➡9 - 1

➡8

And

➡m² + 1

➡(3)² + 1

➡9 + 1

➡10

Therefore , the pythagorean triplet is 6 , 8 and 10

Answer 2

Given ,

A pythagorean triplet in which one member is 12

We know that ,

the general form of pythagorean triplet is given by

For m > 1

$\boxed{ \tt{2m \: , \: m² - 1 \: , \: \: and \: \: m² + 1}}$

Thus ,

➡2m = 6

➡m = 6/2

➡m = 3

Now ,

➡m² - 1

➡(3)² - 1

➡9 - 1

➡8

And

➡m² + 1

➡(3)² + 1

➡9 + 1

➡10

Therefore , the pythagorean triplet is 6 , 8 and 10