find the q.no. 14 okkk
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Sushil Is Now 4 Times As Old As Sunil And 5 Years Ago Sushil Was 7 Times As Old As Sunil And We Need To
Find Their Present Ages.
So Now Let's Move For Solution....
So To Find The Present Ages Of Sushil and Sunil Follow The Simple Steps
Now Let ...
The Present Age Of Sunil Be = X
So According To Question Sushil Is Now 4 times The Age Of Sunil Therefore
Present age Of Sushil = 4x
Now Thier Ages Before 5 Years Are ....
Age Of Sunil 5 Year Ago = X - 5
So
Age Of Sushil Before 5 years = 4x - 5
That Is ...
According To Question It's Said That Sushil Was 7 Times Older Than Sunil before 5 years ...
Therefore
Sushil's Old Age = 7 Times Of Sunil's Onld Age ...
So Now Putting Past Ages Of Sushil And Sunil Here .. we have ....
That Is ....
Now Open Bracket And Find The Product.(LHS)
That Is ...
Now Taking All Variable Terms To LHS and constant To RHS We Have ...
Now Solving Both Side We Have ....
Taking 3 To LHS We Have ...
Therefore We Have ....
So We Have...
And
Therefore Required Answer Is...
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thanks for Question answer is
40years and 10 years
40years and 10 years
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