Question

find the qe whose zeros are 5 and 8​

Answer 1

40, 80,120......... Are the qe whose zeros are 5 and 8

Answer 2

GIVEN:

$\alpha = 5 \\ \beta = 8 \\ \alpha + \beta = 13 \\ \alpha \beta = 40 \\ we \: know \\ {x}^{2} - ( \alpha + \beta ) + \alpha \beta = 0 \\ = > substituting \: from \: above \: values \\ = > {x}^{2} - 13x + 40 = 0 \\ \\ \\ hence \: this \: is \: the \: required \: quadratic \: equation$

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