Question

find the quadrant equations whose roots are the reciprocal of the roots of x^+4x-10=0

Answer 1

roots of x^2+4x-10

-2+√14 & -2-√14

reciprocal of these roots are 
$\frac{1}{ - 2 + \sqrt{14} } and \frac{ - 1}{ 2 + \sqrt{14} }$


sum =
$\frac{2}{5}$

product =
$\frac{1}{10}$

equation =
$10 {x}^{2} 10 {x}^{2} - 4x - 1$

please mark it as the brainliest