Question

2x+3y=6 6x-5y=4 solve by cross multiplication

Answer 1

hope it's helpful for you

Answer 2

Answer:

The value of x is 3/2 and y is 1.

Explanation:

We have the equation

2x+3y=6 -------(Eq-1)

2x+3y=6 -------(Eq-1)6x-5y=4--------(Eq-2)

We can cancel y terms in both the Equation 1 and 2 by making the y same.

So by multiplying 5 with Eq-1, then we get,

$5 \times (2x + 3y) = 5 \times 6$

$10x + 15y = 30$

(opening the bracket)

Let the above will be Equation-3.

By multiplying 3 with Eq-2, we get,

$3 \times (6x - 5y) = 3 \times 4$

$18x - 15y = 12$

(Opening the bracket)

Let the above equation will be Equation-4.

Now, adding Equation-3 and Equation-4, we get

$10x + 15y + 18x - 15y = 30 + 12$

Or,

$28x = 42$

(Canceling 15y and -15y)

Or,

$x = \frac{42}{28}$

Or,

$x = \frac{42 \div 14}{28 \div 14}$

(Converting the fraction to the smallest fraction by Deviding it with 14)

Or,

$x = \frac{3}{2}$

Putting the value of x in Equation-1, we get

$2 \times \frac{3}{2} + 3y = 6$

Or,

$3 + 3y = 6$

Or,

$3y = 6 - 3$

Or,

$3y = 3$

Or,

$y = \frac{3}{3}$

Or,

$y = 1$

Conclusion:

The value of the x is found to be 3/2 and y is 1.