Question

find the quadratic equation from the given roots , which are -7/2 and -3/5

Answer 1

Answer:

x = -7/2 or x = -3/5

x + 7/2 =0 or x + 3 /5 =0

2x + 5= 0 or 5x + 3=0

(2x + 5)(5x + 3) = 0

7x^2 + 23x * -15 =0(ans)

Step-by-step explanation:

Quadratic Equation in Standard Form: ax2 + bx + c = 0. Quadratic Equations can be factored. Quadratic Formula: x = −b ± √(b2 − 4ac) 2a. When the Discriminant (b2−4ac) is: positive, there are 2 real solutions. zero, there is one real solution. negative, there are 2 complex solutions.

There are many quadratic polynomials with the same roots.

If pp and qq are the roots, then the quadratic must be a(x−p)(x−q)a(x−p)(x−q), where aa is any non-zero number. (You can choose aa however you want.)

For example, if p=2/3, and q=7/8, then

(x−23)(x−78)=x2−3724x+712(x−23)(x−78)=x2−3724x+712

That’s with a=1. But, you can see that by choosing a=24 (the least common denominator of the fractions) you can write a different quadratic with the same roots:

24(x−23)(x−78)=24(x2−3724x+712)=24x2−37x+1424(x−23)(x−78)=24(x2−3724x+712)=24x2−37x+14

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