find the quadratic equation whose one of the root is 2 and 5
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x^2 -(alpha +beta) x +alpha beta=0
alpha +beta = 2+5=7
alpha beta =2×5 =10
now
x^2-(7)x +10=0
x^2-7x+10=0
alpha +beta = 2+5=7
alpha beta =2×5 =10
now
x^2-(7)x +10=0
x^2-7x+10=0
soumya834:
tq
Answered by
0
Answer:I
Step-by-step explanation:
Alpha = 2 , beta = 5
Alpha + beta = 7
Alpha. Beta = 10
Eq = x² - (7)x +10
= x²-7x+10
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