find the quadratic equation whose roots are 7 + root 3 and 7 minus root 3
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Answered by
3
Hi there !!
α = 7 +√3
β = 7 - √3
Sum of zeros = α + β = 7 +√3 + 7 -√3
= 14
Product of zeros = αβ = (7 +√3)(7 -√3)
= 7² - 3 = 46
Quadratic equation :-
x² - (α + β)x + αβ
= x² - 14x + 46 ----> required quadratic equation
α = 7 +√3
β = 7 - √3
Sum of zeros = α + β = 7 +√3 + 7 -√3
= 14
Product of zeros = αβ = (7 +√3)(7 -√3)
= 7² - 3 = 46
Quadratic equation :-
x² - (α + β)x + αβ
= x² - 14x + 46 ----> required quadratic equation
Answered by
0
t (x- 7-√3) (x-7+√3)
t[x^2-(7-√3)x-x(7+√3) + 49-3]
t[x^2-14x+46] , where t is a constant which may be positive or negative.
t[x^2-(7-√3)x-x(7+√3) + 49-3]
t[x^2-14x+46] , where t is a constant which may be positive or negative.
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