Question

find the quadratic equation whose zeroes are 2 and -1/3 ?​

Answer 1

Answer:

HOPE THIS WILL BE HELPFUL!!!

Answer 2

Answer:

Let α,β are zeros of quadratic equation

Here, α = 2 and β = -1/3

Now, sum of zeros = α+β = 2+(-1/3) = 2-1/3 = 6-1/3 = 5/3

product of zeros = αβ = 2(-1/3) = -2/3

When zeros are known

then quadratic equation is in the form of K(X2 - X(α+β) + αβ)

= K(X2 - X(5/3) - 2/3)

= K(X2 - 5X/3 - 2/3)

at k = 3

then the quadratic equation is 3(X2-5X/3-2/3)

=3X2-5X-2

the required quadratic eqaution is 3X2 - 5x - 2