Question

find the quadratic equations whose rootsare twice the roots of 2x²-5x+2=0​

Answer 1

Step-by-step explanation:

Let α and β be the root of the givene quation.

Then,α+β=

$\frac{2}{5}$andαβ=$\frac{2}{2}$=1

∴2α+2β

∴(α+β)

∴5(2α)(2β)=4

Sotherequiredequationis:

x²−5x+4=0

xXitzSweetMelodyXx

Answer 2

Answer:

4x^2 - 17x + 16

Step-by-step explanation:

2x^2 - 5x + 2 = 0

2x^2 - 4x -x +2 = 0

2x (x - 2) -1 (x-2) = 0

roots are x = 2, x = 1/2

2x = 4  or 1/4