Question

find the quadratic equations whose rootsare twice the roots of 2x²-5x+2=0


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Answer 1

$\huge\mathtt \red{A} \blue{n} \pink{s} \purple{w} \blue{e} \orange{r}$

Let α and β be the root of the given equation.

Then,α+β= 5/2 and αβ= 2/2 =1

∴2α+2β

∴(α+β)

∴5(2α)(2β)=4

$</p><p>So \: the \: required \: equation \: is: X^2−5x+4=0$

I hope it is helpful for you

@ Aman Jha

Answer 2

Answer:

Letαandβbetherootofthegivenequation.

Then,α+β=

2

5

andαβ=

2

2

=1

∴2α+2β

∴(α+β)

∴5(2α)(2β)=4

Sotherequiredequationis:

x

2

−5x+4=0