Question

Find the quadratic polynomial each with the given number as the sum and products of its zeroes respectively (i) 1/4, -1​

Answer 1

Answer:

Answer given below. Please mark it as brainliest if you find it useful.

Step-by-step explanation:

Let the zeroes be p and q.

∴ p + q = 1/4, pq = -1

Quad. =

  x² - (p+q)x + pq = 0

⇒ x² - 1/4x - 1 = 0

⇒ 4x² - x - 4 = 0

Answer 2

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Answer:$\huge\underline{\bf\red{Solution}:-}$

Given that, sum of zeroes and

product of zeroes given polynomial are 1/4 and -1 respectively.

Let the Quadratic polynomial be ax2 + bx++c and it's zeroes be a and b.

a+b = sum of zeroes = 1/4

ab = product of zeroes -1

Now , ax2 + bx+c =k (x-a) ( x-b)

where k is any constant

= k[ x2 - (a +b) x+ab ]

= k[ x2 -1/4x+)(-1) ]

=K[ x2-1/4 x-1]

for different value of k, we get different quadratic polynomials.