find the quadratic polynomial if sum of zeros is equal to √2 and product of zeros is equal to -12 hence find the zeros of polynomial
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let x and y be zeroes of it.
therefore x×y=-12=-b/a
also
x+y=√2=c/a
comparing it we get a=1 b=12 c=√2
so p(x)=ax²+bx+c
=1x²+12x+√2
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Answer:
Step-by-step explanation:
Polynomial formed= x^2-√2x -12
√D= (-√2)^2-4*(-12)
=4+48=√56
Hence , alpha= -√2+√56/2
Beta=-√2-√56/2
damab:
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