Question

Find the quadratic polynomial sum of whose zeros is 2 root 3 and product is 2

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

Any Quadratic Polynomial is of the form,

$p(x) = K [ x^{2} - (\alpha +\beta )x + \alpha \beta ]$

where K is any integer and  $\alpha$ and $\beta$ are its roots.

Now,

Sum of roots =  $\alpha +\beta$ = 2√3

product of roots = $\alpha\beta$ = 2

therefore,

$p(x) = x^{2} - 2\sqrt{3} \ x \ + 2$