Question

find the quadratic polynomial sum of whose zeros is 8 and their product is 12 hence find the zero of the polynomial​

Answer 1

SOLUTION___✒️

Sum of the zeroes of required polynomial, S= 8

& Product of zeroes of required polynomial, P= 12

Now, p(x)= x^2-Sx+P

p(x)=x^2-8x+12

Now, zeroes of p(x) are given by solving the equation p(x) =0

So, p(x)=0

=x^2 - 8x + 12= 0

=x^2 -6x-2x +12 =0

= x(x-6) - 2(x-6)= 0

=(x-6) (x-2)= 0

= x -6 =0 or x- 2= 0

= x= 6 or x= 2

So, zeroes of p(x) are 2& 6 ans.

⚙️MARK BRAINLIEST✓✓