Question

find the value of cot (-15π/4)

Answer 1

here is ur ans i hope it is right

Answer 2

Answer:

1

Step-by-step explanation:

We have to find the value of cot (-15π/4)

So,

$cot (\dfrac {-15\pi}4) = -cot(\dfrac{15\pi}4)\\\\-cot (3\dfrac {3\pi}4)$

We know that the value of cotx repeats after an interval of 2π.

So 4π = 2 × 2π  

Now,

$= -cot (4\pi - \dfrac 14\pi)\\=-(-cot\ \dfrac14 \pi)\\\\=cot\ (\dfrac 14 \pi)\\= cot (\dfrac 14 \times 180^o)\\\\= cot 45^o\\= 1$

So, the value of cot (-15π/4) is 1.