Math, asked by fariaparween04, 10 months ago

find the quadratic polynomial the some of whose roots is√2 and their product is 1/3​

Answers

Answered by Aparna2904
3

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HEY FRIEND,

HERE IS YOUR ANSWER >>>

let \:  \alpha and \:  \beta be \: the \: zeroes \: of \: the \: polynomial \\ given \\  \alpha  +  \beta  =  \sqrt{2}  \\  \alpha  \beta  =  \frac{1}{3}  \\ we \: have \\ p(x) =  a({x}^{2}  - ( \alpha  +  \beta )x +  \alpha  \beta)  \\ p(x) =  a({x}^{2}  -  \sqrt{2}x +  \frac{1}{3}) \\ put \: a = 3 \\ p(x) =  3{x}^{2} - 3 \sqrt{2}  + 1

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