Question

find the quadratic polynomial the sum and product of whose zero root 2 and minus 3 upon 2​

Answer 1

Step-by-step explanation:

the sum of zeros = √2

product of zeros = -3/2

let the zeros be

$\alpha$

and

$\beta$

then

$\alpha + \beta = \sqrt{2}$

and

$\alpha \beta = - 3 \div 2$

thus, polynomial =

$x ^{2} { - ( \alpha + } \beta )x + \alpha \beta$

$x ^{2} - \sqrt{2} x - 3 \div 2$

2x^2 -2√2x -3 is the required polynomial...

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