find the quadratic polynomial , the sum and product of whose zeroes are √3 and 1/√3 . verify the relationship between the zeros and coefficients of polynomial
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Answered by
1
Answer:
I think this is your Answer !
Let the zeroes of the quadratic polynomial be α=1,β=−3
Then, α+β=1+(−3)=−2
αβ=1×(−3)=−3
Sum of zeroes =α+β=−2
Product of zeroes =αβ=−3
Then, the quadratic polynomial =x2−( sum of zeroes )x+ product of zeroes =x2−(−2)x+(−3)=x2+2x−3
Verification:
Sum of zeroes =α+β=1+(−3)=−2 or
=− Coefficient of x2 Coefficient of x=−1(2)=−2
Product of zeroes =αβ=(1)(−3)=−3 or
= Coefficient of x2 Constant term =1−3=−3
So, the relationship between the zeroes and the coefficients is verified.
Answered by
2
Answer:
sum = root3 , so - b/a = root3 - (i) product = 1/root 3 , so c/a =1/root3 - (ii)
On comparing 1. and 2. , a = root3 , b = (-3) and c = 1 , so p(x) = root3x square - 3x + 1
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