find the quadratic polynomial,the sum and product of whose zeroes are root 2 and -3/2 respectively.find its zeroes
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Answered by
6
sum of zeroes = √2
product of zeroes = -3/2
required quadratic polynomial = x²-(Sum of zeroes)x + product of zeroes
= x²-(√2)x + (-3/2)
= x² - √2x - 3/2
product of zeroes = -3/2
required quadratic polynomial = x²-(Sum of zeroes)x + product of zeroes
= x²-(√2)x + (-3/2)
= x² - √2x - 3/2
Answered by
4
We know that polynomial equation =
x^2 -x(sum of zeroes) + (product of zeroes) = 0
given sum of zeroes= 2
product of zeroes= -3/2
x^2 - (2)x + (-3/2)=0
x^2 -2x -3/2 =0
LCM
[(2)x^2 -2x(2) -3]/2 = 0
2x^2 - 4x - 3 =0 is the quadratic polynomial..
x^2 -x(sum of zeroes) + (product of zeroes) = 0
given sum of zeroes= 2
product of zeroes= -3/2
x^2 - (2)x + (-3/2)=0
x^2 -2x -3/2 =0
LCM
[(2)x^2 -2x(2) -3]/2 = 0
2x^2 - 4x - 3 =0 is the quadratic polynomial..
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