find the quadratic polynomial the sum of whose zeroes is -10 and product of its zeores is -39
Answers
Answered by
1
Answer:
x^2 + 10x -39 = 0
Step-by-step explanation:
let the zeroes of the polynomial are ,α and β
therefore ,
αβ = -39
α + β = -10
quadratic eq.
x^2 -(α+β)x + αβ = 0
x^2 + 10x -39 = 0
Answered by
1
Answer:
SUM = -10
PRODUCT = -39
POLYNOMIAL = k [x²-[sum ] x +product ]
1[ x²-[-10]x+[-39]
x²+10x-39 Is the required polynomial .
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